Calculus

Lesson 7 of 14

Advanced Integration Techniques

Partial fractions, trig substitution, improper integrals, and a strategy decision tree.

Partial fractions

Consider ∫x+2x2−1dx\int \frac{x+2}{x^2-1}dx. Substitution fails (numerator isn't the derivative of the denominator) and by-parts goes nowhere. Instead, factor and split:

x+2(x−1)(x+1)=Ax−1+Bx+1\frac{x+2}{(x-1)(x+1)} = \frac{A}{x-1} + \frac{B}{x+1}

Solving A(x+1)+B(x−1)=x+2A(x+1) + B(x-1) = x + 2 gives A=32A = \frac{3}{2}, B=−12B = -\frac{1}{2}, so the integral is 32ln⁡∣x−1∣−12ln⁡∣x+1∣+C\frac{3}{2}\ln|x-1| - \frac{1}{2}\ln|x+1| + C. This works whenever the denominator factors into distinct linear terms.