Stochastic Calculus

Geometric Brownian Motion for Dummies

Up 50% then down 40% leaves you at 90%: why the typical path of a stock grows at μ − σ²/2 while its average grows at μ.

What to remember

  • Gains and losses come from different bases: (1+r)(1−r)=1−r2(1 + r)(1 - r) = 1 - r^2, so an up-and-down round trip of size rr loses r2r^2.
  • The typical (median) path grows at μ−σ2/2\mu - \sigma^2/2; the average grows at μ\mu.
  • GBM: ST=S0exp⁡((μ−σ2/2)T+σWT)S_T = S_0 \exp\big((\mu - \sigma^2/2)T + \sigma W_T\big), so STS_T is lognormal with mean S0eμTS_0 e^{\mu T} and median S0e(μ−σ2/2)TS_0 e^{(\mu - \sigma^2/2)T}.
  • P(ST>E[ST])=1−Φ(σT/2)P(S_T > E[S_T]) = 1 - \Phi(\sigma\sqrt T / 2), which goes to 00 as TT grows: a few extreme paths carry the average.
  • The same −σ2/2-\sigma^2/2 appears in Black-Scholes d2d_2, leveraged funds and Kelly betting.
  • Each daily tick contributes ln⁡(1+x)≈x−12x2\ln(1 + x) \approx x - \tfrac12 x^2, and the squared ticks add up to σ2t\sigma^2 t, so the naive solution eμt+σWte^{\mu t + \sigma W_t} runs ahead of the true path by 12σ2t\tfrac12\sigma^2 t in the exponent.
Read the lessonGeometric Brownian Motion and Volatility Drag, with a checkpoint at the end.